​LeetCode刷题实战609：在系统中查找重复文件

示例 1：

输入：paths = ["root/a 1.txt(abcd) 2.txt(efgh)","root/c 3.txt(abcd)","root/c/d 4.txt(efgh)","root 4.txt(efgh)"]
输出：[["root/a/2.txt","root/c/d/4.txt","root/4.txt"],["root/a/1.txt","root/c/3.txt"]]

示例 2：

输入：paths = ["root/a 1.txt(abcd) 2.txt(efgh)","root/c 3.txt(abcd)","root/c/d 4.txt(efgh)"]
输出：[["root/a/2.txt","root/c/d/4.txt"],["root/a/1.txt","root/c/3.txt"]]

HashMap< String, List < String >> map = new HashMap < > ();
        for (String path: paths) {
            String[] values = path.split(" ");
            for (int i = 1; i < values.length; i++) {
                String[] name_cont = values[i].split("\\(");
                name_cont[1] = name_cont[1].replace(")", "");
                List < String > list = map.getOrDefault(name_cont[1], new ArrayList < String > ());
                list.add(values[0] + "/" + name_cont[0]);
                map.put(name_cont[1], list);
            }
        }
        List < List < String >> res = new ArrayList< >();
        for (String key: map.keySet()) {
            if (map.get(key).size() > 1)
                res.add(map.get(key));
        }
        return res;